Comparing two files in C language.

Operations on More than one File. 

 #include<stdio.h>

#include<stdlib.h>

#include<string.h>

int main(int argc, char const* argv[])

{

    FILE* file_ptr1;

    FILE* file_ptr2;

    file_ptr1 = fopen("test1.txt", "r");

    file_ptr2 = fopen("test2.txt", "r");

    char word1 [15], word2 [15];

    int total_count = 0;

    while (fscanf(file_ptr1, "%s", word1) != EOF)

    {

        int count = 0;

        fseek(file_ptr2, 0, SEEK_SET);

        while (fscanf(file_ptr2, "%s", word2) != EOF)

        {

            if (strcmp(word1, word2) == 0)

            {

                count++;

            }

        }

        if (count == 0)

        {

            total_count++;

            printf("\"%s\" ---> not in file.\n", word1);

        }

    }

    printf("%d words are not in file.\n", total_count);

    fclose(file_ptr1);

    fclose(file_ptr2);

    return 0;

}

Reading and writing in files ( C language )

File operations in C.

 #include<stdio.h>

#include<stdlib.h>

#include<string.h>

int main(int argc, char const* argv[])

{

    FILE* file_ptr;

    file_ptr = fopen("test2.txt", "w");

    fprintf(file_ptr, "This is first file of c .\n");

    char* data = "happy to programming file operations .";

    fputs(data, file_ptr);

    fclose(file_ptr);

    file_ptr = fopen("test2.txt", "r");

    //feek(file_pointer,start away from,set the ptr) function  

    fseek(file_ptr, 1, SEEK_SET);

    char arr;

    for (int i = 0; i <= 5; i++)

    {

        fscanf(file_ptr, "%c", &arr);

        printf("%d--->%c\n", i, arr);

    }

    fclose(file_ptr);

    return 0;

}

File Handling in C language.

File operations-writing and reading in files.

 #include <stdio.h>

int main(int argc, char const* argv[])

{

// creating first file

// storing pointer of start of file

    FILE* first_file;

    first_file = fopen("test1.txt", "w");

    // checking if file is opened correctly

    if (first_file == 0)

    {

        printf("Not able to find file.");

    }

    else

    {

    // writes the content in file

        fprintf(first_file, "This is first file of c language .\n"); //--------------

        char* data = "I am happy to programming file operations .";

        fputs(data, first_file); //---------------

        // closing file

        fclose(first_file);

    }

// Reading the file content

    first_file = fopen("test1.txt", "r");

    char content [50];

    int i = 0;

// gets the line or(gets characters upto the index given(-1))

    while (fgets(content, 6, first_file) != NULL)

    {

        printf("\n%d\n", i);

        i++;

        // fgets(content,50,first_file);               //using fgets() function

        printf("%s", content);

    }

// //printing by using fscanf() function

// while (fscanf(first_file, "%s", content) != EOF)         //EOF ==> end of file

//     {

//     printf("%s\n", content);

//     }

// // fscanf(first_file, "%c", content);

// // printf("%c", *content);

    fclose(first_file);

    return 0;

}

Structures in C (2)

structures in C.

 #include<stdio.h>

struct student

{

    char* name;

    int roll_no;

    float perc_prev_yr;

    int admiss_yr;

};

int main(int argc, char const *argv[])

{

    struct student student_1;

    struct student student_2;

    struct student student_3;

    struct student student_4;

    student_2.name = "Madan";

    student_2.roll_no = 2002;

    student_2.perc_prev_yr = 78.31;

    student_2.admiss_yr = 2020;

    student_3.name = "Mohan";

    student_3.roll_no = 1950;

    student_3.perc_prev_yr = 85.0;

    student_3.admiss_yr = 2019;

    student_4.name = "Raman";

    student_4.roll_no = 1730;

    student_4.perc_prev_yr = 80.50;

    student_4.admiss_yr = 2017;

    printf("Name :%s\n", student_3.name);

    printf("Roll_number :%d\n", student_3.roll_no);

    printf("Previous Year Percentage :%.2f\n", student_3.perc_prev_yr);

    printf("Admission Year :%d\n", student_3.admiss_yr);

    return 0;

}

Structures in C language

struct keyword-use and operations

 #include <stdio.h>

struct busi_biscuit

{

    char* type;

    int min_price_rs;

    int gm_wgt;

};

int main()

{

    // creating struct of given type

    struct busi_biscuit parle_G;

    // creating struct of given type

    struct busi_biscuit Jim_jam;

    //assigning values to it

    parle_G.type = "Non-creamy";

    parle_G.min_price_rs = 5;

    parle_G.gm_wgt = 50;

    Jim_jam.type = "creamy";

    Jim_jam.min_price_rs = 25;

    Jim_jam.gm_wgt = 150;

    printf("Jim_jam(type): %s\n" , Jim_jam.type);

    printf("Jim_jam.minimum price(Rs) : %d Rs\n" , Jim_jam.min_price_rs);

    printf("Jim_jam Weight(gm) : %d gm \n" , Jim_jam.gm_wgt);

    return 0;

}

Use of conditional statements-Using switch in C language.

Use of switch in C language.

 #include <stdio.h>

int main(int argc, char const *argv[])

{

    int a=11;

    while (a != 10)

    {

        // switch case

        printf("Enter Number :");

        scanf("%d", &a);

        switch (a)

        {

        case 0:

        {

            printf("%d :zero is the number.\n", a);

            break;

        }

        case 1:

        {

            printf("%d :one is the number.\n", a);

            break;

        }

        case 2:

        {

            printf("%d :two is the number.\n", a);

            break;

        }

        case 3:

        {

            printf("%d :three is the number.\n", a);

            break;

        }

        default:

        {

            printf("Not valid input.\n");

            break;

        }

        }

    }

    return 0;

}

Hacker-rank problem -marks sum problem of students. ( C language )

//Hackerrank problem -marks sum problem of students.

#include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>

int marks_summation(int* marks , int number_of_students , char gender)

{

    int sum = 0 , i;

    if ( gender == 'b' )

    {

        for ( int i = 0; i < number_of_students; i += 2 )

        {

            sum += marks[i];

        }

    }

    else

    {

        for ( int i = 1; i < number_of_students; i += 2 )

        {

            sum += marks[i];

        }

    }

    return sum;

}

int main()

{

    int number_of_students;

    char gender;

    int sum;

    scanf("%d" , &number_of_students);

    int* marks = (int*)malloc(number_of_students * sizeof(int));

    for ( int student = 0; student < number_of_students; student++ )

    {

        scanf("%d" , (marks + student));

    }

    scanf(" %c" , &gender);

    sum = marks_summation(marks , number_of_students , gender);

    printf("%d" , sum);

    free(marks);

    return 0;

}

Euler Problem-finding difference between sum of square and square of sum problem. ( C language )

solving maths problems using C language.

 /*

The sum of the squares of the first ten natural numbers is,

 1^2 + 2^2 + 3^2 + ... 10^2 = 385

The square of the sum of the first ten natural numbers is,

(1+2+3+4...........+10)^2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers

 and the square of the sum is .

 3025-385=2640

Find the difference between the sum of the squares of the first one hundred

natural numbers and the square of the sum.

 */

#include <stdio.h>

int main()

{

    int sum_upto;

    sum_upto = 100;

    int sum_of_squares = 0;

    int square_of_sum = 0;

    for (int i = 1; i <= sum_upto; i++)

    {

        sum_of_squares += (i * i);

        square_of_sum += ( i );

    }

    square_of_sum *= square_of_sum;

    int diff = square_of_sum - sum_of_squares;

    printf("Difference is : %d", diff);

    return 0;

}

Use of mathematical operations and implementation (C language )

Problem-Finding the sum of digits of five digit number.

 #include <stdio.h>

#include <string.h>

#include <math.h>

#include <stdlib.h>

int main()

{

    int n;

    scanf("%d", &n);

    // Complete the code to calculate the sum of the five digits on n.

    int num;

    int base = 10000;

    int sum = 0;

    // printf("%d\n",(num-(num%base))/base );

    // printf("%d\n",(num%base));

    for (int i = 1; i <= 5; i++)

    {

        num = (n - (n % base)) / base;

        n = (n % base);

        base /= 10;

        sum += num;

    }

    printf("%d\n", sum);

    return 0;

}